In the given question, two equations numbered l and II are given. Solve both the equations and mark the appropriate answer.
I. 3√3x^{2} - √27 = 0
II. ∛125y^{2} - 125 = 0
Given:
I. 3√3x2 - √27 = 0
II. ∛125y2 - 125 = 0
Calculation:
From I,
3√3x2 - √27 = 0
⇒ 3√3x2 = √27
⇒ 3√3x2 = 3√3
⇒ x2 = (3√3)/(3√3)
⇒ x2 = 1
⇒ x = ±√1
⇒ x = ±1
⇒ x = 1 or -1
From II,
∛125y2 - 125 = 0
⇒ 5y2 = 125
⇒ y2 = 125/5
⇒ y2 = 25
⇒ y = ±√25
⇒ y = ±5
⇒ y = 5 or -5
Comparison between x and y (via Tabulation):
Value of x |
Value of y |
Relation |
1 |
5 |
x < y |
1 |
-5 |
x > y |
-1 |
5 |
x < y |
-1 |
-5 |
x > y |
∴ x = y or relation between x and y can not be established.